If KE of a given particle is doubled, its momentum will be:

Doubled

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Tripled

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Increases by

\sqrt{2}

times

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Remains unchanged

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Solution

The correct option is B Increases by $\sqrt{2}$ times
The relation between kinetic energy $(K)$ and momentum $(p)$ is given by, $K = \frac{p^{2}}{2 m}$ where $m$ be the mass of the body
So, $p = \sqrt{2 m K}$
If kinetic energy is doubled, the momentum becomes, $p^{'} = \sqrt{2 m (2 K)} = \sqrt{2} p$

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If KE of a given particle is doubled, its momentum will be:

The correct option is B Increases by √2 timesThe relation between kinetic energy (K) and momentum (p) is given by, K=p22m where m be the mass of the bodySo, p=√2mKIf kinetic energy is doubled, the momentum becomes, p′=√2m(2K)=√2p