Question

If KE of the particle of mass, $m$, performing Uniform Circular Motion in a circle of radius, $r$, is $E$. Find the acceleration of the particle

• A. $\frac{2E}{mr}$
• B. ${\left(\frac{2E}{mr}\right)}^2$
• C. $2Emr$
• D. $\frac{4E}{mr}$

Answer 1

The correct option is A $\frac{2E}{mr}$

Let, $v$ be the velocity of the particle.

Then, energy = $E=\frac{1}{2}m{v}^2$

Acceleration of a particle in circular motion = $\frac{v^2}{r}=\frac{2E/m}{r}$

$=\frac{2E}{mr}$