Question

if kinetic energy of a body increases by 0.1% the percentage increase in momentum will be ?

Answer 1

Dear Student,


$$\begin{gathered} letthemassbemandspeedbeu \\ afterincreasethespeedbev \\ \frac{m{v}^2}{2}=\frac{1.001m{u}^2}{2} \\ v=\sqrt{1.001}u \\ initialmomentum=mu \\ finalmomentum=mv=m\left(\sqrt{1.001}u\right) \\ percentageincrease=\frac{m\left(\sqrt{1.001}u\right)-mu}{mu}*100=\left(\sqrt{1.001}-1\right)100=0.05percent. \\ Regards \end{gathered}$$