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Question

If kx−2ky+15=0 passes through the point (3,−1), then what is the value of k?

A
1
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B
2
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C
-3
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D
3
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Solution

The correct option is C -3
As (3,1) passes through kx2ky+15=0, (3,1) satisfies the given equation.

Putting x=3,y=1 in the given equation,
(k×3)(2×k×1)+15=0
3k+2k+15=0
k=3

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