If $k x - 2 k y + 15 = 0$ passes through the point $(3, - 1)$ , then what is the value of $k$ ?

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Solution

The correct option is C -3
As $(3, - 1)$ passes through $k x - 2 k y + 15 = 0$ , $(3, - 1)$ satisfies the given equation.

Putting $x = 3, y = - 1$ in the given equation,
$(k \times 3) - (2 \times k \times - 1) + 15 = 0$
$\Rightarrow 3 k + 2 k + 15 = 0$
$\Rightarrow k = - 3$

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If kx−2ky+15=0 passes through the point (3,−1), then what is the value of k?

The correct option is C -3As (3,−1) passes through kx−2ky+15=0, (3,−1) satisfies the given equation. Putting x=3,y=−1 in the given equation, (k×3)−(2×k×−1)+15=0 ⇒ 3k+2k+15=0 ⇒ k=−3

If $k x - 2 k y + 15 = 0$ passes through the point $(3, - 1)$ , then what is the value of $k$ ?

The correct option is C -3
As $(3, - 1)$ passes through $k x - 2 k y + 15 = 0$ , $(3, - 1)$ satisfies the given equation.

Putting $x = 3, y = - 1$ in the given equation,
$(k \times 3) - (2 \times k \times - 1) + 15 = 0$
$\Rightarrow 3 k + 2 k + 15 = 0$
$\Rightarrow k = - 3$