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Question

If l2i+m2i+n2i=1 and
lilj+mimj+ninj=0 for ij
where i,j{1,2,3} and
A=l1m1n1l2m2n2l3m3n3,then|A|=

A
4
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B
3
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C
1
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D
2
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Solution

The correct option is C 1
A.AT=l1m1n1l2m2n2l3m3n3l1l2l3m1m2m3n1n2n3

=⎢ ⎢l21+m21+n21l1l2+m1m2+n1n2l1l3+m1m2+n1n3l1l2+m1m2+n1n2l22+m22+n22l2l3+m2m3+n2n3l1l3+m1m2+n1n3l2l3+m2m3+n2n3l23+m23+n23⎥ ⎥=100010001
A.AT=I|A.AT|=1
|A|2=1,
|A|=|AT|
|A|=±1

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