If L and R are respectively inductance and resistance- then the dimensions of L-R will beA- M 0 L 0 T -1B- M 0 LT 0C- M 0 L 0 TD- Cannot be represented in terms of M - L and T

The correct option is C M^0L^0TE=LdI/dt and [E]=[JC^ 1]=[ML^2T^ 2]× nbsp; [AT]^ 1 =ML^2T^ 3A^ 1 From this, we get dimensional formula of inductance [L] = ML^ ...

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Standard XII

Physics

Solar Cell

If L and R ar...

Question

If $L$ and $R$ are respectively inductance and resistance, then the dimensions of $\frac{L}{R}$ will be

M^{0} L^{0} T^{- 1}

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M^{0} L T^{0}

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M^{0} L^{0} T

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Cannot be represented in terms of

M, L

and

T

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Solution

The correct option is C $M^{0} L^{0} T$
$E = L \frac{d I}{d t}$ and $[E] = [J C^{- 1}] = [M L^{2} T^{- 2}] \times [A T]^{- 1}$
$= M L^{2} T^{- 3} A^{- 1}$
From this, we get dimensional formula of inductance
$[L] = M L^{2} T^{- 2} A^{- 2}$

Similarly, we know $E = I R$
From this, dimensional formula of resistance
$[R] = M L^{2} T^{- 3} A^{- 2}$
$∴ [\frac{L}{R}] = M^{0} L^{0} T$ (Dividing the two)

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If L and R are respectively inductance and resistance, then the dimensions of LR will be

The correct option is C M0L0TE=LdIdt and [E]=[JC−1]=[ML2T−2]×[AT]−1 =ML2T−3A−1 From this, we get dimensional formula of inductance [L]=ML2T–2A–2 Similarly, we know E=IR From this, dimensional formula of resistance [R]=ML2T–3A–2 ∴[LR]=M0L0T (Dividing the two)

If $L$ and $R$ are respectively inductance and resistance, then the dimensions of $\frac{L}{R}$ will be