If L.C.M and H.C.F of two expressions are $(x^{2} + 6 x + 8)$ and $(x + 1)$ respectively and one equations is $x^{2} + 3 x + 2$ then what will be the other equations?

x^{2} + 5 x + 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} - 5 x + 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} + 4 x + 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} - 4 x + 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x^{2} + 5 x + 4$
Given $L C M = (x + 4) (x + 2), H C F = (x + 1)$

Factorising $x^{2} + 3 x + 2$ , we get ,

$\Rightarrow$ $x^{2} + 3 x + 2$

$= x^{2} + x + 2 x + 2$

$= (x + 1) (x + 2)$

$\Rightarrow$ The second equation will be $H C F \times (x + 4)$

$\Rightarrow$ $(x + 1) (x + 4) = x^{2} + 5 x + 4$

Suggest Corrections

Similar questions

(x^{2} + 6 x + 8) (x + 1)

(x + 1)

x^{2} + 3 x + 2

(x^{2} + 6 x + 8) (x + 1)

(x + 1)

x^{2} + 3 x + 2

p (x) = x^{2} + 6 x + 8, q (x) = x^{2} + 5 x + 6, r (x) = x^{2} + 4 x + 3

s (x) = x^{2} + 5 x + 4

(x + 5), (x^{2} + 4 x + 16)

x^{2} + 9 x + 20

f (x) = x^{2} + 3 x + 2

q (x) = x^{2} - 4 x + 4

x^{2} - 4

Join BYJU'S Learning Program