Question

If $L$ is the inductance, ${}^{\prime }{i}^{\prime }$ is current in the circuit, $\frac{1}{2}{Li}^2$ has the dimensions of:

• A. Work
• B. Power
• C. Pressure
• D. Force

Answer 1

Answer: (A)

Work

$L\to M{L}^2{I}^{-2}{T}^{-2}$
$I\to I$
${LI}^2=\left(M{L}^2{I}^{-2}{T}^{-2}\right)I^2=M{L}^2{T}^{-2}\to \left(unitofwork\right)$
$Power=f\times v=ML{T}^{-2}\times L{T}^{-1}=M{L}^2{T}^{-3}$
$Pressure=f/A=\frac{ML{T}^{-2}}{L^2}={ML}^{-1}{T}^{-2}$
$force=M^1{L}^1{T}^{-2}$