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Byju's Answer
Standard XII
Physics
Acceleration in 2D
If l b̅×c̅ ...
Question
If
l
(
¯
b
×
¯
c
)
+
m
(
¯
c
×
¯
a
)
+
n
(
¯
a
×
¯
b
)
=
0
And at least one of
l
,
m
,
n
is not zero, then the vectors
¯
a
,
¯
b
,
¯
c
are
A
Parallel
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B
Coplanar
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C
Mutually perpendicular
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D
None of these
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Open in App
Solution
The correct option is
D
Coplanar
Given that,
l
(
¯
¯
b
×
¯
¯
c
)
+
m
(
¯
¯
c
×
¯
¯
¯
a
)
+
n
(
¯
¯
¯
a
×
¯
¯
b
)
=
0
Taking Dot product with
¯
¯
¯
a
;
l
[
¯
¯
¯
a
.
¯
¯
b
.
¯
¯
c
]
=
0
Dot product with
¯
¯
b
;
m
[
¯
¯
¯
a
.
¯
¯
b
.
¯
¯
c
]
=
0
Dot product with
¯
¯
c
;
n
[
¯
¯
¯
a
.
¯
¯
b
.
¯
¯
c
]
=
0
⇒
[
¯
¯
¯
a
.
¯
¯
b
.
¯
¯
c
]
=
0
⇒
¯
¯
¯
a
.
¯
¯
b
and
¯
¯
c
are co-planar.
Then,
OPtion
B
is correct answer.
Suggest Corrections
0
Similar questions
Q.
If
¯
a
,
¯
b
,
¯
c
are three vectors such that
|
¯
a
|
=
5
,
∣
∣
¯
b
∣
∣
=
12
,
|
¯
c
|
=
13
and
¯
a
,
¯
b
,
¯
c
are perpendicular to
¯
b
+
¯
c
,
¯
c
+
¯
a
,
¯
a
+
¯
b
respectively, then
∣
∣
¯
a
+
¯
b
+
¯
c
∣
∣
=
Q.
If for non-zero vectors
¯
a
,
¯
b
,
¯
c
¯
a
×
¯
b
=
¯
c
and
¯
b
×
¯
c
=
¯
a
, then prove that
|
¯
b
|
=
1
.
Q.
If
¯
a
,
¯
b
and
¯
c
are unit vectors, then
∣
∣
¯
a
−
¯
b
∣
∣
2
+
∣
∣
¯
b
−
¯
c
∣
∣
2
+
|
¯
c
−
¯
a
|
2
does not exceed
Q.
If
¯
a
,
¯
b
,
¯
c
,
are non - coplanar vectors and
¯
p
=
¯
b
×
¯
c
[
¯
b
¯
c
¯
a
]
,
¯
q
=
¯
c
×
¯
a
[
¯
c
¯
a
¯
b
]
,
¯
r
=
¯
a
×
¯
b
[
¯
a
¯
b
¯
c
]
then :
(
¯
a
−
¯
b
−
¯
c
)
⋅
¯
p
−
(
¯
b
−
¯
c
−
¯
a
)
⋅
¯
q
+
(
¯
c
−
¯
a
−
¯
b
)
⋅
¯
r
=
Q.
If
¯
a
,
¯
b
,
¯
c
are unit vector and
¯
c
=
¯
a
+
¯
b
, then
|
¯
a
−
¯
b
|
is
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