Let M=x√x3√x4√x5√x⋅⋅⋅
=x√x⋅√3√x⋅√3√4√x5√x⋅⋅⋅
=x√x⋅√3√x⋅√3√4√x⋅√3√4√5√x⋅⋅⋅
=x⋅x12⋅x12⋅13⋅x12⋅13⋅14⋅x12⋅13⋅14⋅15⋅⋅⋅
=x1+12+12⋅3+12⋅3⋅4+12⋅3⋅4⋅5+⋅⋅⋅
=x11+11⋅2+11⋅2⋅3+11⋅2⋅3⋅4+⋅⋅⋅
=x11!+12!+13!+14!+15!⋅⋅⋅
M=xe−1 (∵e=1+11!+12!+13!+...)
So,
L=logxM⇒L=e−1=1.72
⌈L⌉=2