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Question

If l,m are real lm then the roots of the equation (lm)x25(l+m)x2(lm)=0 are

A
real and equal
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B
non real complex
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C
real and unequal
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D
none of these
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Solution

The correct option is D real and unequal
(lm)x25(l+m)x2(lm)=0
D=25(l+m)2+8(lm)2>0
Therefore, the roots are real and unequal.
Ans: C

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