If $l, m, n$ are in arithmetic progression, then the straight line $l x + m y + n = 0$ will pass through the point:

$(- 1, 2)$

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$(1, - 2)$

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$(1, 2)$

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$(2, 1)$

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Solution

The correct option is B
$(1, - 2)$

Explanation for the correct answer.
The given equation of line is $l x + m y + n = 0 . . . . . . . (1)$
As $l, m, n$ are in arithmetic progression, so
$2 m = l + n \Rightarrow l - 2 m + n = 0 . . . (2)$
By comparing the coefficient of $(1)$ and $(2)$ , we get
$x = 1, y = - 2$
Therefore, the straight line $l x + m y + n = 0$ will pass through the point $(1, - 2)$ .
Hence, option B is correct.

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If l,m,n are in arithmetic progression, then the straight line lx+my+n=0 will pass through the point:

If $l, m, n$ are in arithmetic progression, then the straight line $l x + m y + n = 0$ will pass through the point: