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Question

If l,m,n are real, lm, then the roots of the equation (lm)x25(l+m)x2(lm)=0, are

A
real and unequal
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B
None of the above
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C
no solution
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D
real and equal
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Solution

The correct option is D real and equal
Discriminant of the given equation is
D=25(l+m)2+8(lm)2(lm)2>0 (lm), (l+m)20D>0

Hence, the roots are real and unequal.

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