Question

If l,m,n are three lines such that l||m and $n\perp l$, prove that $n\perp m$.

Answer 1

Given: l, m,n are three lines such that l||m and $n\perp l$
To prove: $n\perp m$
Proof: $\because l||m$ and n is the transversal.
$\therefore \angle 1=\angle 2$ (Corresponding angles)
But $\angle 1={90}^0$ $(\because n\perp l)$
$\therefore \angle 2={90}^0$
$\therefore n\perp m$