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Question

If λ1 and λ2 are the wavelength of the first numbers of the Lyman and Paschen series respectively. Then λ1:λ2 ____________

A
1:30
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B
1:3
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C
7:50
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D
7:108
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Solution

The correct option is D 7:108
For Lyman series 1λ1=R[1121n2]
1λ1=R[11122] [for the first number, n=2]
1λ1=R[414]
λ1=43R ....(i)
For Paschen series
1λ2=R[132142] [for n=4]
λ2=1447R ....(ii)
So, λ1:λ2=43R×7R144=7:108

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