If λ1 and λ2 are the wavelength of the first numbers of the Lyman and Paschen series respectively. Then λ1:λ2 ____________
A
1:30
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7:50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
7:108
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D7:108 For Lyman series 1λ1=R[112−1n2] 1λ1=R[11−122] [for the first number, n=2] 1λ1=R[4−14] λ1=43R ....(i) For Paschen series 1λ2=R[132−142] [for n=4] λ2=1447R ....(ii) So, λ1:λ2=43R×7R144=7:108