Question

# If $$\lambda_1$$ and $$\lambda_2$$ denote the wavelengths of de Broglie waves for electrons in the first and second Bohr orbits in a hydrogen atom, then $$\lambda_1/\lambda_2$$ is equal to :

A
2
B
12
C
14
D
4

Solution

## The correct option is B $$\dfrac{1}{2}$$The De-Broglie wavelengths can be given by:$$\lambda =\dfrac{h}{mv}..(1)$$Since mass of electron remains same, we get$$\dfrac{\lambda _{1}}{\lambda _{2}}=\dfrac{v_{2}}{v_{1}}..(2)$$Now, by Bohr's postulates, we know that velocity of electron in $$n^{th}$$ orbit in inversely proportional to $$n$$. Hence, Answer= $$1/2$$.Physics

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