If Lamp $A$ is less bright than Lamp $B$ ; Lamp $B$ is brighter than Lamp $C$ is as bright as Lamp $D$ ; Lamp $B$ is brighter than Lamp $D$ ; Lamp $D$ ; Lamp $D$ is brighter than Lamp $A$ ; then which lamp is the brightest?

Lamp

A

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Lamp

B

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Lamp

C

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Lamp

D

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Solution

The correct option is B Lamp $B$
From the conditions given in question, we can get the following relations :
Lamp A < Lamp B
Lamp C < Lamp B
Lamp C = Lamp D
Lamp A < Lamp D, which can be combined as Lamp A<D=C<B.
So, Lamp B is brightest.

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If Lamp A is less bright than Lamp B; Lamp B is brighter than Lamp C is as bright as Lamp D; Lamp B is brighter than Lamp D; Lamp D; Lamp D is brighter than Lamp A; then which lamp is the brightest?

The correct option is B Lamp BFrom the conditions given in question, we can get the following relations :Lamp A < Lamp BLamp C < Lamp BLamp C = Lamp DLamp A < Lamp D, which can be combined as Lamp A<D=C<B.So, Lamp B is brightest.

If Lamp $A$ is less bright than Lamp $B$ ; Lamp $B$ is brighter than Lamp $C$ is as bright as Lamp $D$ ; Lamp $B$ is brighter than Lamp $D$ ; Lamp $D$ ; Lamp $D$ is brighter than Lamp $A$ ; then which lamp is the brightest?

The correct option is B Lamp $B$
From the conditions given in question, we can get the following relations :
Lamp A < Lamp B
Lamp C < Lamp B
Lamp C = Lamp D
Lamp A < Lamp D, which can be combined as Lamp A<D=C<B.
So, Lamp B is brightest.