274

You visited us 274 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Addition and Subtraction of Algebraic Expression

If LCM of a4 ...

Question

If LCM of $a^{4} b^{3}$ , $a^{3} b^{6}$ and $a^{4} b^{8}$ is $a^{x} b^{y}$ , then the value of $\frac{y}{x}$ = ______.

$2$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$5$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$1$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$0.5$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$2$

LCM of $a^{4} b^{3}$ , $a^{3} b^{6}$ and $a^{4} b^{8}$ is $a^{4} b^{8} .$

$∴ x = 4$ and $y = 8$

So, $\frac{y}{x}$ = $2$

Suggest Corrections

Similar questions

LCM of $a^{3} b^{3}$ , $a^{5} b^{6}$ and $a^{4} b^{8}$ is $a^{x} b^{y}$ . Value of $y - x$ = 3.

Q. If a and b are different positive primes such that

(i)

{(\frac{a^{- 1} b^{2}}{a^{2} b^{- 4}})}^{7} \div (\frac{a^{3} b^{- 5}}{a^{- 2} b^{3}}) = a^{x} b^{y}

, find x and y.

(ii)

{(a + b)}^{- 1} (a^{- 1} + b^{- 1}) = a^{x} b^{y}

, find x + y + 2.

If a and b are different primes such that $(i) {[\frac{a^{- 1} b^{2}}{a^{2} b^{- 4}}]}^{7} \div [\frac{a^{3} b^{- 5}}{a^{- 2} b^{3}}] = a^{x} b^{y}, f i n d x a n d y .$

$(i i) (a + b)^{- 1} (a^{- 1} + b^{- 1}) = a^{x} b^{y}, f i n d x + y + 2.$

Q. The van't Hoff factor for weak electrolyte

A_{x} B_{y}

, if

(n = x + y)

can be given as:

Q. The solubility of a sparingly soluble salt

A_{x} B_{y}

in water at

25^{o} C

1.4 \times 10^{- 4} M

. The solubility product is

1.1 \times 10^{- 11}

. The possible value(s) of x and y is/are:

Join BYJU'S Learning Program

If LCM of a4b3, a3b6 and a4b8 is axby, then the value of yx = ______.

The correct option is A 2 LCM of a4b3, a3b6 and a4b8 is a4b8. ∴x=4 and y=8 So, yx = 2

If LCM of $a^{4} b^{3}$ , $a^{3} b^{6}$ and $a^{4} b^{8}$ is $a^{x} b^{y}$ , then the value of $\frac{y}{x}$ = ______.

The correct option is A
$2$

LCM of $a^{4} b^{3}$ , $a^{3} b^{6}$ and $a^{4} b^{8}$ is $a^{4} b^{8} .$

$∴ x = 4$ and $y = 8$

So, $\frac{y}{x}$ = $2$