polynomial 1,P1 =(y-3)^a (2y+1)^b (y+13)^7
polynomial 2,P2 =(y-3)^4 (2y+1)^9 (y.+13)^c
LCM of P1 and P2 ,P3 =(y-3)^6 (2y+1)^10(y+13)^7,
WE can take term by term
For P1 (y-3)^4 ,P2 =(y-3)^a and P3 =(y-3)^6
For LCm of (y-3)^4 and (y-3)^a =(y-3)^4+a
So Given 4+a=6
Then least value of a =6-4 =2
For P1 =(2y+1)^b ,P2 = (2y+1)^9 and P3 =(2y+1)^10
For LCm of (2y+1)^b and (2y+1)^9 =(2y+1)^9+b
So given 9+b=10
Then least value of b =10-9 =1
For P1 =(y+13)^7 ,P2 =(y.+13)^c and P3 =(y+13)^7
For LCm of (y+13)^7 and (y.+13)^c =(y+13)^7+c
So given 7+c=7
Then least value of b =7-7 =0
THere fore least value of a+b+c =2+1+0=3