If LCM of two numbers is the greater of the two numbers, then its HCF
A
Will always be 1
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B
Will beLCMSmallernumber
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C
Will be the smaller number
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D
Will be equal to LCM
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Solution
The correct option is C Will be the smaller number Let a, b are the two numbers such that a < b. As we know, LCM×HCF=a×b Here LCM = b (given in the question) So, b×HCF=a×b HCF = a HCF≤a,b≤LCM So, HCF will be the smaller number.