If ${(1 + x + 2 x^{2})}^{20} = 0 + a_{1} x + a_{2} x^{2} + . . . . . . + a_{40} x^{40}$ then $a_{1} + a_{3} + a_{5} + . . . . . . + a_{37}$ equals -

2^{19} (2^{20} - 21)

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2^{20} (2^{19} - 19)

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2^{19} (2^{20} + 21)

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None of these

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Solution

The correct option is A $2^{19} (2^{20} - 21)$

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Similar questions

Q. If

{(1 + x + 2 x^{2})}^{20} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . . + a_{10} x^{40}

, then

a_{1} + a_{3} + a_{5} + . . . . . . + a_{39}

equals

Q. If

{(1 + x + 2 x^{2})}^{20} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . + a_{39} x^{39} + a_{40} x^{40}

then find the value of

a_{0} + a_{1} + a_{2} + . . . . . . + a_{38}

If $(1 + x + 2 x^{2})^{20} = a_{0} + a_{1} + a_{2} x^{2} + . . . + a_{40} x^{40}, t h e n a_{1} + a_{3} + a_{5} + . . . + a_{37} e q u a l s$ :

Q. If

{(1 + x + {2 x}^{2})}^{20} = a_{0} + a_{1} x + a_{2} x^{2} + . . . . . . . . + a_{40} x^{40}

then find the value of

a_{0} + a_{2} + . . . . . . + a_{38}

$(1 + x + 2 x^{2})^{20}$ = $a_{0} + a_{1} x + a_{2} x^{2}$ ................... $a_{40} x^{40}$ , If $a_{0} + a_{1} + a_{2} + a_{3} . . . . . . . . . . . . . . . . . . a_{40} = 2^{a}$

$a_{0} - a_{1} + a_{2} - a_{3} . . . . . . . . . . . . . . . . . . . . . . a_{40} = 2^{b}$ . Find the value of a + b

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If (1+x+2x2)20=0+a1x+a2x2+......+a40x40 then a1+a3+a5+......+a37 equals -

The correct option is A 219(220−21)

If ${(1 + x + 2 x^{2})}^{20} = 0 + a_{1} x + a_{2} x^{2} + . . . . . . + a_{40} x^{40}$ then $a_{1} + a_{3} + a_{5} + . . . . . . + a_{37}$ equals -

The correct option is A $2^{19} (2^{20} - 21)$