If $| 4 x - 4 | = 8$ and $| 5 y + 10 | = 15$ , what is the smallest possible value of $x y$ ?

- 20

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- 15

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- 5

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- 1

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Solution

The correct option is C $- 15$
$| 4 x - 4 | = 8$
$4 x - 4 = 8 ⟹ x = 3$
$4 x - 4 = - 8 ⟹ x = - 1$

$| 5 y + 10 | = 15$
$5 y + 10 = 15 ⟹ y = 1$
$5 y + 10 = - 15 ⟹ y = - 5$

Possible values of $x y$ are $3, - 15, - 1, 5$

Smallest possible value $- 15$

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No. of Students	$5$	$6$	$15$	$10$	$5$	$4$	$2$	$1$

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