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Question

If |a|=2 ,|b|=3 , |c|=4 and a+b+c=0 then the value of bc+ca+ab is equal to

A
19/2
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B
19/2
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C
29/2
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D
29/2
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Solution

The correct option is C 29/2
|a|=2 ,|b|=3 , |c|=4 and a+b+c=0 (a+b+c)(a+b+c)=|a|2+|b|2+|c|2+2(ab+bc+ca) 0=29+2(ab+bc+ca) (ab+bc+ca)=292

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