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Question

If |a×b|=4 and|a.b|=2, then|a|2|b|2 is equal to

A
2
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B
6
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C
8
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D
20
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Solution

The correct option is D 20
|a×b|=|a||b|sinθ=4 , also, |a,b|=|a||b|cosθ=2
Squaring and adding a both, we get
|a|2|b|2sin2θ+|a|2+|b|2cos2θ=16+4=20
|a|2|b|2(sin2θ+cos2θ)=20
|a|2|b|2=20
Option (D) is correct

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