If - - 2 and - - then tan- equals

The correct option is C tanβ+2tanγ α+β=π 2⇒α=π 2 β⇒ tanα =cot β ⇒ tanα tan β=1 Next, β+γ=α ⇒α β=γ⇒tanα tanβ1+tanα tanβ=tanγ ⇒ tan ...

146

You visited us 146 times! Enjoying our articles? Unlock Full Access!

Sin(A+B)Sin(A-B)

If α+β =π 2...

Question

If $(α + β) = \frac{π}{2}$ and $(β + γ) = α$ , then $t a n α$ equals

2 (t a n β + t a n γ)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

t a n β + t a n γ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

t a n β + 2 t a n γ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 t a n β + t a n γ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

I f α + β = \frac{π}{2} a n d β + γ = α, t h e n t a n α e q u a l s

x^{2} + y^{2} + z^{2} = r^{2}

tan α = \frac{x y}{z r}, tan β = \frac{y z}{x r}, tan γ = \frac{Z X}{y r}

α + β + γ =

tan β = \frac{2 sin α sin γ}{sin (α + γ)}

tan α, tan β, tan γ

α \neq 0 a n d γ \neq 0 a n d β \neq \frac{π}{2}

tan β = \frac{2 sin α sin γ}{sin (α + γ)}

tan α, tan β, tan γ

α \neq 0 a n d γ \neq 0 a n d β \neq \frac{π}{2}

tan α + tan β + tan γ - tan α tan β tan γ = \frac{sin (α + β + γ)}{cos α cos β cos γ}

Join BYJU'S Learning Program