wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If ∣ ∣abcbcacab∣ ∣=k(a+b+c)(a2+b2+c2bccaab), then k=

A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1
Given,
k(a+b+c)(a2+b2+c2bccaab)

=∣ ∣abcbcacab∣ ∣

=a(bca2)b(b2ac)+c(abc2)

=abca3+abcb3+abcc3

=3abca3b3c3

=(a3+b3+c33abc)

=(a+b+c)(a2+b2+c2abbcca)

=(1)(a+b+c)(a2+b2+c2abbcca)

By comparing we get
k=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon