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Question

If ∣∣ ∣∣x−15x7x2−1x−182x3x0∣∣ ∣∣=ax3+bx2+cx+d then value of c is given by

A
1
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B
12
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C
15
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D
17
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Solution

The correct option is C 17
We have,
∣ ∣x15x7x2x182x3x0∣ ∣=ax2+bx2+cx+dDifferentiate with respect to x∣ ∣ ∣150(x21)(x1)82x3x0∣ ∣ ∣+∣ ∣x15x72x102x3x0∣ ∣+∣ ∣ ∣x15x7(x21)(x1)8230∣ ∣ ∣=3ax2+2bx+cputtingx=0∣ ∣150118000∣ ∣+∣ ∣107010000∣ ∣+∣ ∣107118230∣ ∣=c=0+01(024)+7(3+2)=c=247=cc=17Hence,optionDiscorrectanswer.

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