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Question

If ∣ ∣1+x1x1x1x1+x1x1x1x1+x∣ ∣ =0 then x=

A
1,1
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B
1,1
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C
0,1
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D
0,3
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Solution

The correct option is D 0,3
∣ ∣1+x1x1x1x1+x1x1x1x1+x∣ ∣=0
C1C1+C2+C3
∣ ∣3x1x1x3x1+x1x3x1x1+x∣ ∣=0
(3x)∣ ∣11x1x11+x1x11x1+x∣ ∣=0
R1R1R2,R2R2R3
(3x)∣ ∣02x002x2x11x1+x∣ ∣=0
4x2(3x)=0
x=3,0

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