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Byju's Answer
Standard XII
Mathematics
Definition of a Determinant
If | x+1 ...
Question
If
∣
∣
∣
x
+
1
x
−
1
x
−
3
x
+
2
∣
∣
∣
=
∣
∣
∣
1
−
1
1
3
∣
∣
∣
, then write the value of
x
.
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Solution
∣
∣
∣
x
+
1
x
−
1
x
−
3
x
+
2
∣
∣
∣
=
∣
∣
∣
1
−
1
1
3
∣
∣
∣
(
x
+
1
)
(
x
+
2
)
−
(
x
−
1
)
(
x
−
3
)
=
(
3
+
1
)
x
2
+
3
x
+
2
−
(
x
2
−
4
x
+
3
)
=
4
x
2
+
3
x
+
2
−
x
2
+
4
x
−
3
=
4
7
x
−
1
=
4
7
x
=
5
x
=
5
7
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]
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