If - x-1 x-1 x-3 x-2 - - 1 -1 1 3 - then write the value of x-

x+1 amp; x 1 x 3 amp; x+2 = 1 amp; 1 1 amp; 3 (x+1)(x+2) (x 1)(x 3)=(3+1) x ^ 2 +3x+2 ( x ^ 2 4x+3)=4 x ^ 2 +3x+2 ...

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Definition of a Determinant

If | x+1 ...

Question

If $∣ ∣ ∣ \begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 1 & - 1 1 & 3 \end{matrix} ∣ ∣ ∣$ , then write the value of $x$ .

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Solution

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Similar questions

|\begin{matrix} x + 1 & x - 1 \\ x - 3 & x + 2 \end{matrix}| = |\begin{matrix} 4 & - 1 \\ 1 & 3 \end{matrix}|

∣ ∣ ∣ \begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 4 & - 1 1 & 3 \end{matrix} ∣ ∣ ∣

x,

∣ ∣ ∣ \begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 4 & - 1 1 & 3 \end{matrix} ∣ ∣ ∣

[\begin{matrix} x + 1 & x - 1 x - 3 & x + 2 \end{matrix}] = [\begin{matrix} 4 & - 1 1 & 3 \end{matrix}]

x

\sqrt{2} - 1

\frac{1}{x} .

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