Question

If $({\cos }^2\theta +\frac{1}{cose{c}^2\theta })+4=x$ then what is the value of $x$?

• A. $3$
• B. $5$
• C. $6$
• D. $4$

Answer 1

The correct option is B $5$

$({\cos }^2\theta +\frac{1}{cose{c}^2\theta })+4=x$
$\therefore ({\cos }^2\theta +{\sin }^2\theta )+4=x(\because \sin \theta =\frac{1}{cosec\theta })$
$\therefore 1+4=x$
$\therefore 5=x$.