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Question

If ⎢ ⎢ ⎢ ⎢ ⎢ ⎢[1(ab)2]a2(ab)2+2ab⎥ ⎥ ⎥ ⎥ ⎥ ⎥=1 and a+b=5, then find a and b.

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Solution

[1(ab)2]a2(ab)2+2ab=1

[1(ba)2]a2(a+b)=1

[a2b2](a+b)=1

ab=1 ....(1)
Given, a+b=5 ....(2)
On solving eq (1) and (20, we get a=3,b=2

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