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Standard Logarithm

If 3/2 x 2-1/...

Question

If ${(\frac{3}{2} x^{2} - \frac{1}{3 x})}^{9}$ is expanded in descending powers of x, then $7^{t h}$ term is given by:

7/18

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16x/27

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16/27

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-(7x/18)

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Solution

The correct option is A
7/18

$T_{7} = T_{6 + 1} =^{9} C_{6} (\frac{3}{2} x^{2})^{3} (- \frac{1}{3 x})^{6}$ = $\frac{7}{18}$

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