if $(m_{i}, \frac{1}{m_{i}}), i = 1, 2, 3, 4$ are concyclic points then the value of $m_{1} m_{2} m_{3} m_{4}$ is

1

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0

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Solution

The correct option is A $1$
Hence, Option (A) is the correct answer.

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Similar questions

If $(m_{i}, \frac{1}{m_{i}})$ , i = 1, 2, 3, 4 are con - cyclic points, then the value of $m_{1}, m_{2}, m_{3}, m_{4}$ is

(m_{i}, 1 / m_{i}), m_{i} > 0, i = 1, 2, 3, 4

m_{1} m_{2} m_{3} m_{4} = 1

If $(m_{i}, \frac{1}{m_{i}})$ , i = 1, 2, 3, 4 are con - cyclic points, then the value of $m_{1} m_{2} m_{3} m_{4}$ is

f (m_{i}, \frac{1}{m_{i}})

i = 1, 2, 3, 4

m_{1} m_{2} m_{3} m_{4}

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