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Question

If [abc]=2 then [a+2b,b2c,c+3a]=

A
6
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B
10
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C
8
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D
12
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Solution

The correct option is C 10
[a+2b,b2c,c+3a]
=∣ ∣110012301∣ ∣[abc]
=[1(10)1(0+6)+0][abc]
=(16)(2)=5×2=10

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