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Question

If [a×b b×c c×a]=λ[a b c]2 then λ is equal to

A
2
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B
3
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C
0
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D
1
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Solution

The correct option is D 1
[a×b b×c c×a]=(a×b).{(b×c)×(c×a)}
=(a×b).([b c a]c[b c c]a)
=[b c a][a b c]
=[a b c]2
Hence, λ=1

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