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Question

If (secα+tanα)(secβ+tanβ)(secγ+tanγ)=tanαtanβtanγ, then (secαtanα)(secβtanβ)(secγtanγ)=

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Solution

Solution -
(secα+tanα)(secβ+tanβ)(secγ+tanγ)=tanαtanβtanγ __ (1)
Now,
Multiply (secαtanα)(secβtanβ)(secγtanγ) in both sides
1=tanαtanβtanγ(secαtanα)(secβtanβ)(secγtanγ)
Because sec2θtan2θ=1
(secαtanα)(secβtanβ)(secγtanγ)=1tanαtanβ.tanγ
=cotαcotβcotγ.

1103997_1191311_ans_04c6c67f1c0043389fd0fd91b91bae98.jpg

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