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Question

If |a|=3,b=1,|c|=4 and a+b+c=0, then the value of ab+bc+ca is

A
26
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B
13
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C
26
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D
13
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Solution

The correct option is B 13
Now,
(a+b+c)2=(a+b+c)(a+b+c)
0=|a|2+b2+|c|2+2(ab+bc+ca)
0=(3)2+(1)2+(4)2+2(ab+bc+ca)
(ab+bc+ca)=262=13

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