If - a- - - b- - - c- -3 and a- b- -b- c- c-a-4- If p-q-r- is the reciprocal system of a-b-c- then 85 - p- q- r- - is equal to

The correct option is C √(17) We take #160; [abc]^2 =a̅,.a̅ amp; a̅.b̅ amp; a̅.c̅ #160; #160;b̅.a̅ amp;b̅.b̅ #160; amp; b̅ ...

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Continuity in an Interval

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Question

If $| \to a | = ∣ ∣ \to b ∣ ∣ = | \to c | = 3$ and $\to a . \to b . = \to b . \to c = \to c . \to a = 4.$ If $\to p, \to q, \to r$ is the reciprocal system of $\to a, \to b, \to c,$ then $85$ $[\to p \to q \to r]$ is equal to

\sqrt{17}

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2 \sqrt{17}

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3 \sqrt{17}

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5 \sqrt{17}

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Similar questions

\to a, \to b, \to c

\to p, \to q, \to r

(\to a \times \to p) + (\to b \times \to q) + (\to c \times \to r)

[\begin{matrix} \to a & \to b & \to c \end{matrix}] = 1

\frac{\to a . \to b \times \to c}{\to c \times \to a . \to b} + \frac{\to b . \to c \times \to a}{\to a \times \to b . \to c} + \frac{\to c . \to a \times \to b}{\to b \times \to c . \to a}

| \to a | = | \to b | = | \to c | = 1

\to a + \to b + \to c = \to 0

\to a . \to b + \to b . \to c + \to c . \to a = \frac{- 3}{2}

(\to p + \to q)^{2} = | \to p |^{2} + | \to q |^{2} + 2 \to p . \to q

[\to a \to b \to c] = 2

\frac{\to a . (\to b \times \to c)}{(\to c \times \to a) . \to b} + \frac{\to b . (\to c \times \to a)}{(\to a \times \to b) . \to c} + \frac{\to c . (\to a \times \to b)}{(\to b \times \to c) . \to a} =

| \to a | = 1, | \to b | = 2, | \to c | = 3

\to a + \to b + \to c = 0

\to a . \to b + \to b . \to c + \to c . \to a

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