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Question

If |x3|<2x+9, then x lies in the interval

A
(,2)
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B
(2,0)
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C
(2,)
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D
(2,)
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E
(12,2)
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Solution

The correct option is A (,2)
Given, |x3|<2x+9
(2x+9)<x3<2x+9
2x9<x3 and x3<2x+9
3x<6 and x<12
x>2 and x>12
x>2
Therefore, x(2,)

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