If x-12-y2-1-12-32- find x and y

We have, #10; #10; ( x+12,y2 1 )=( 13,32 #10;) #10; #10;On comparing both side and we get, #10; #10; x+12=13 #10; #10; x=13 12 ...

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Standard X

Mathematics

Addition of Rational Expressions

If x+12,y2-...

Question

If $(x + \frac{1}{2}, \frac{y}{2} - 1) = (\frac{1}{2}, \frac{3}{2})$ , find $x$ and $y$

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Solution

We have,

$(x + \frac{1}{2}, \frac{y}{2} - 1) = (\frac{1}{3}, \frac{3}{2})$

On comparing both side and we get,

$x + \frac{1}{2} = \frac{1}{3}$

$x = \frac{1}{3} - \frac{1}{2}$

$x = \frac{2 - 3}{6}$

$x = - \frac{1}{6}$

Now,

$\frac{y}{2} - 1 = \frac{3}{2}$

$\frac{y}{2} = \frac{3}{2} + 1$

$\frac{y}{2} = \frac{5}{2}$

$y = 5$

Hence, this is the answer.

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If (x+12,y2−1)=(12,32), find x and y

We have, (x+12,y2−1)=(13,32) On comparing both side and we get, x+12=13 x=13−12 x=2−36 x=−16 Now, y2−1=32 y2=32+1 y2=52 y=5 Hence, this is the answer.

If $(x + \frac{1}{2}, \frac{y}{2} - 1) = (\frac{1}{2}, \frac{3}{2})$ , find $x$ and $y$