If x- 1 3 - y 2 -1 - 1 2 - 3 2 - then find x and y-

x+13= 12 x= 12 13 x= 16 ... Answer y2 1= 32 y2= 32+1 y=5 ... Answer ...

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Standard XII

Mathematics

Derivative from First Principle

If x+ 1 3 ,...

Question

If $(x + \frac{1}{3}, \frac{y}{2} - 1) = (\frac{1}{2}, \frac{3}{2})$ , then find x and y.

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Solution

$x + \frac{1}{3} = \frac{1}{2}$

$x = \frac{1}{2} - \frac{1}{3}$

$x = \frac{1}{6}$ ... $A n s w e r$

$\frac{y}{2} - 1 = \frac{3}{2}$

$\frac{y}{2} = \frac{3}{2} + 1$

$y = 5$ ... $A n s w e r$

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(x + \frac{1}{3}, \frac{y}{2} - 1) = (\frac{1}{2}, \frac{3}{2})

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Find the equation of the circle which circumscribes the triangle formed by the lines:
(i) $x + y + 3 = 0, x - y + 1 = 0$ and $x = 3$
(ii) $2 x + y - 3 = 0, x + y - 1 = 0$ and $3 x + 2 y - 5 = 0$
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Q. Find the equation of the circle which circumscribes the triangle formed by the lines
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If (x+13,y2−1)=(12,32), then find x and y.

x+13=12x=12−13x=16...Answery2−1=32y2=32+1y=5...Answer

If $(x + \frac{1}{3}, \frac{y}{2} - 1) = (\frac{1}{2}, \frac{3}{2})$ , then find x and y.

$x + \frac{1}{3} = \frac{1}{2}$

$x = \frac{1}{2} - \frac{1}{3}$

$x = \frac{1}{6}$ ... $A n s w e r$

$\frac{y}{2} - 1 = \frac{3}{2}$

$\frac{y}{2} = \frac{3}{2} + 1$

$y = 5$ ... $A n s w e r$