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(a + b)^2 Expansion and Visualisation

If x + 1 /...

Question

If $(x + \frac{1}{x}) = 16$ , find the value of $x^{2} + \frac{1}{x^{2}}$ .

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Solution

$x + \frac{1}{x} = 16$

$(x + \frac{1}{x})^{2} = 256$

$x^{2} + \frac{1}{x^{2}} + 2 = 256$

$x^{2} + \frac{1}{x^{2}} = 254$

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