If $(x + y) = 10$ and $(x - y) = 2$ find, $x^{2} - y^{2}$

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Solution

Given that,

$(x + y) = 10$ and $(x - y) = 2$

We have to find, $x^{2} - y^{2}$

Now,

$x^{2} - y^{2} = (x + y) (x - y)$

$x^{2} - y^{2} = 10 - 2$

$x^{2} - y^{2} = 8$

Hence, this is the answer.

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