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B
Is more than 3
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C
Is less than 12
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D
Lies between 6 and 12
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Solution
The correct option is D Is less than 12 ∵|z1−1|<1 ⇒|z1|−|1|<1 (By triangle inequality) ⇒|z1|<2...(i) Similarly |z2−2|<2 ⇒|z2|−|2|<2 ⇒|z2|<4...(ii) and |z3−3|<3 ⇒|z3|−|3|<3⇒|z3|<6...(iii) On adding Eqs. (i),(ii),(iii) we get |z1|+|z2|+|z3|<2+4+6 ⇒|z1|+|z2|+|z3|<12...(iv) By using triangular inequality |z1+z2+z3|≤|z1|+|z2|+|z3| ⇒|z1+z2+z3|<12 (From Eq. (iv))