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Question
If |z1|=15 and |z2−3−4i|=5, then
If |z1|=15 and |z2−3−4i|=5, then
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Solution
The correct options are
A |z1−z2|min=5
C |z1−z2|max=15
Circle1:|z1|=15Circle2:|z2−3−4i|=5
From the fig. min|z1−z2| will be Radius(Circle1)−Diameter(Circle2).
⟹min(|z1−z2|)=15−10=5
⟹max(|z1−z2|)=radius of circle 1=15
Hence, option 'A' and 'D' are correct.
A |z1−z2|min=5
C |z1−z2|max=15
Circle1:|z1|=15Circle2:|z2−3−4i|=5
From the fig. min|z1−z2| will be Radius(Circle1)−Diameter(Circle2).
⟹min(|z1−z2|)=15−10=5
⟹max(|z1−z2|)=radius of circle 1=15
Hence, option 'A' and 'D' are correct.
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