Given that |z+2−i|=5
Now, |3z+9−7i|=3∣∣∣z+2−i+(1−4i3)∣∣∣≤3(|z+2−i|+∣∣∣1−4i3∣∣∣)=3(5+53)=20
Therefore, M4=5
Ans: 5