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Question

If |zi|<1, then |z+126i|

A
<14
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B
<16
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C
>14
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D
=14
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Solution

The correct option is A <14
Given |zi|<1
Now |z+126i|=|(zi)+(125i)|
|zi|+|125i|[|z1+z2||z1|+|z2|]
<1+13=14
Hence |z+126i|<14

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