If |z−i|≤2 and z0=13+5i then the maximum value of |iz+z0| is
A
15
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B
-15
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C
2+√194
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D
√194−2
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Solution
The correct option is A 15 |z−i|≤2 z lies on and in the inner part of the circle |z−i|≤2 z0=13+5i From the fig: max(|iz+z0|) will be the distance between point A & point B=[radius of circle (r)] + [distance between point A and center of the circle (d(AC))]. max(|iz+z0|)=max(|z−iz0|)=max(|z−(−5+13i)|)=r+d(AC) ⇒max(|iz+z0|)=2+√(0−(−5))2+(1−13)2=15 Ans: A