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Question

if|z|=4 and arg z=5π6,then z=

A
232i
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B
23+2i
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C
23+2i
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D
3+i
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Solution

The correct option is C 23+2i
Given,
|z|=4 and argz=5π6
Now,
Z=|z|cos(5π6)+i|z|sin(5π6)

Z=4×(3)2+i×4×12

Z=23+2i

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