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Question

If |z|=4 and arg z=5π6 then z=?

A
232i
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B
23+2i
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C
23+2i
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D
3+i
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Solution

The correct option is C 23+2i

We have,

|z|=4

arg(z)=5π6

Therefore,

z=|z|(cos(5π6)+isin(5π6))

z=4(32+i2)

z=4(3+i2)

z=2(3+i)

Hence, this is the answer.


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